-x^2-5x+5000=0

Solution for -x^2-5x+5000=0 equation:

-x^2-5x+5000=0

We add all the numbers together, and all the variables

-1x^2-5x+5000=0

a = -1; b = -5; c = +5000;
Δ = b2-4ac
Δ = -52-4·(-1)·5000
Δ = 20025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20025}=\sqrt{225*89}=\sqrt{225}*\sqrt{89}=15\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-15\sqrt{89}}{2*-1}=\frac{5-15\sqrt{89}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+15\sqrt{89}}{2*-1}=\frac{5+15\sqrt{89}}{-2}
$